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The dataset generation failed
Error code: DatasetGenerationError
Exception: EmptyDataError
Message: No columns to parse from file
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.12/site-packages/datasets/builder.py", line 1568, in _prepare_split_single
for key, record in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 609, in wrapped
for item in generator(*args, **kwargs):
^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/packaged_modules/folder_based_builder/folder_based_builder.py", line 386, in _generate_examples
for pa_metadata_table in self._read_metadata(downloaded_metadata_file, metadata_ext=metadata_ext):
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/packaged_modules/folder_based_builder/folder_based_builder.py", line 295, in _read_metadata
csv_file_reader = pd.read_csv(metadata_file, iterator=True, dtype=dtype, chunksize=chunksize)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/streaming.py", line 73, in wrapper
return function(*args, download_config=download_config, **kwargs)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/utils/file_utils.py", line 1199, in xpandas_read_csv
return pd.read_csv(xopen(filepath_or_buffer, "rb", download_config=download_config), **kwargs)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 1026, in read_csv
return _read(filepath_or_buffer, kwds)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 620, in _read
parser = TextFileReader(filepath_or_buffer, **kwds)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 1620, in __init__
self._engine = self._make_engine(f, self.engine)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/readers.py", line 1898, in _make_engine
return mapping[engine](f, **self.options)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/pandas/io/parsers/c_parser_wrapper.py", line 93, in __init__
self._reader = parsers.TextReader(src, **kwds)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "pandas/_libs/parsers.pyx", line 581, in pandas._libs.parsers.TextReader.__cinit__
pandas.errors.EmptyDataError: No columns to parse from file
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1320, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 911, in stream_convert_to_parquet
builder._prepare_split(
File "/usr/local/lib/python3.12/site-packages/datasets/builder.py", line 1447, in _prepare_split
for job_id, done, content in self._prepare_split_single(
^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.12/site-packages/datasets/builder.py", line 1604, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
video
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Hello friends welcome back to my channel without any doubt I am Khushali here in today's video we will learn how we can know by just looking at any number that it is divisible by ok so let's
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start quickly first of all see I have written the rule of two here what is written 0 2 4 6 8 and even numbers ok that means whenever we are given an even number at the end of any number
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then that number will be divisible by two ok for example suppose we are given 12 six what is its last number it is six
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this is an even number ok so we will be able to divide it by two ok for example 4564 ok what is its last number it is four this is also divisible by two so this will be
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divisible by two ok now let's see the next rule of three see what I have written here sum of the digits ok so what do we have to do in this with whatever number we are given
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We have to sum all the digits, that is, we have to total them.
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For example, we have been given the number 147. Ok, so let's make its total.
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1 + 4 5 5 + 7 will become 12. Ok, so 12 is divisible by three. 3 * 4 is 12, right. So this number will be divisible by three.
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Ok, next example, suppose 126 is given, what will we do?
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We will add the total of the numbers. 1 + 2 3 3 + 6 9. Ok, so 3 * 3 is 9, which means this number will also be divisible by three. Ok, let's see the next rule. See
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what is the rule of four. Last two digits and double zero. That means, like what we did in two, we noticed the last one digit, right.
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So, what do we have to do in four, we have to notice the last two digits. For example, we have been given the number 164. Ok, so what do we have to do in last two? We have to see the digits,
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what is the last two digits, here it is 64 which is divisible by four, 16 * 4 is 64, so this number will be divisible by four, okay then suppose we have been given 1600, okay
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so what is in its last two digits, there is double zero, so whenever there is double zero, that digit will also be divisible by four, okay now let's see the next example, what have I written here, let's see the rule for five, the
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last digit should be zero and five, okay for example, we have been given the number 96 505, okay so what is in its last, there is five, so this will also be divisible by five, if
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we have been given 6993 0, okay what is in the last, there is zero, so this will also be divisible by five, okay next rule, what have I written for six, I am
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divisible by 2 and 3, okay so what is the rule here, any number, whatever it is, is divisible by both two and three It
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should be divisible by both two and three. For example, we have been given the number 924. Okay, so what we have to check is whether it should be divisible by both two and three.
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First, let's check by two.
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What is the last number of this number? If it is four, then it is divisible by two. Now let's see if it is divisible by three. So, let's make the total. 9 + 2 is 11.
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11 + 4 is 15. Okay, so see, 3 * 5 is 15. This means that it is divisible by two and also by three.
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So, if this number is divisible by two and also by three, then it means that this number will be divisible by six.
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Okay, let's take another example.
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Suppose we are given 7200. Let's first check if it is divisible by two.
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Yes, there is a zero at the end, so it will be divisible by two. Now, let's check if it is divisible by three. See, 7 + 2 9 9 + 0 9 9 + 0 9 Okay, so look, nine is
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divisible by three. 3 * 3 is 9, right?
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So, this number is divisible by both two and three, which means it is divisible by six.
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Okay, so let's move on to the next rule. Let's see what the rule for seven is. Let's double the last digit and subtract the substratum from the remaining numbers. Okay, so what we have to do is
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double the last digit and then subtract that doubled number from the remaining numbers.
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Okay, so after subtracting, the number we get should either be divisible by seven or what should happen? It should be zero. Okay, so let's look at an example. Suppose
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we are given the number 4 1 3, what will we do? If we double the last digit, it will become six.
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So, we will subtract 6 from 41, which will become 35. Okay, so look, 35 is divisible by seven, which means that this number is divisible by seven. Okay, let's
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take another example, suppose 84, what will we do, we will double the last digit, it will become eight. If we subtract eight from eight, it will become zero. Okay, so this number will also be divisible by seven. Okay, let's see the next rule, what is the
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last three digits of eight? Okay, so what did we do in two, we looked at one digit.
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In last four, we looked at two digits. And what do we do in eight, we have to look at three digits.
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Okay, so the last three digits should be divisible by eight, or there should be triple zero at the end. Okay, for example, we have been given a number
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488. Okay, so let's see if the last three digits are divisible by eight. Yes, see, 11 becomes 888, which means this number will be divisible by eight.
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Okay, suppose we have been given a number 3600. Okay, so what is the last one, it means it will also be divisible by eight. Okay, let's see the next rule, what is the meaning of nine, even
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ten, even of digits. What we have to do is we have to total the digits given to us and we have to total that total as well ok for example
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3708 ok so what will be its total see 3 + 7 is 10 10 = 0 10 + 8 will become 18 ok now we have got 18 now 1 + 8 will become 9 ok
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so we have got nine see 9 is divisible by 9 means this will be divisible by nine ok so what we have to do is total the total ok sum
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the sum of digits ok this total should either be divisible by nine or it should be zero ok now next let us see what is the rule of 10 see the last digit should
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simply be zero it is a very easy rule suppose we have been given 806 0 the last digit is zero so it will be divisible by 10 ok
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next let us see What is the rule of 11, sum of alternate and substrate, okay, so let us understand this through an example,
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suppose we have been given the numbers 3 4 3 2, okay, so what we have to do is we have to total the alternate numbers, see 3 + 3, what will
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be 6s, okay, now from here we will take the alternate, 4 + 2 will become 6s, okay, now we have to subtract this, if six is taken out of six, it will become zero, okay, so
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after subtracting this, the number we get should either be divisible by 11, or what should be zero, okay, like it was here, either what should be zero, or it should be divisible by nine,
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similarly it will happen here also, okay, so what will be this number, it will be divisible by 11, so let us see another example, what we have to do is we have to total the alternate numbers,
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so see, 2 + 8 10 10 10 + 4 14 OK Now let's add the total of the remaining alternate numbers.
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1 + 2 will be 3 14 - 3 will be 11. So, 11 is divisible by 11, which means this number will also be divisible by 11.
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OK Now let's see the next rule for 12. It is divisible by 3 and then OK So the number should be divisible by both three and four. Same rule as the rule for six.
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We have been given the number 5508. OK So, let's see if it is divisible by three.
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5 + 5 10 10 + 0 10 + 8 18 So, 18 is divisible by three, which means this number will be divisible by three. OK Now let's see if it is divisible by four.
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Its last two digits, 08, are divisible by four. Meaning this number will be divisible by four as well, meaning this number is divisible by both three and four,
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meaning this number will be divisible by 12, okay so I hope you have understood the rules and I would suggest you to please make notes of it
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so that you can refer to these rules and do tell me by commenting how you liked my video and if you want a video on any particular topic then do tell me that too, I will try to
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[Music] welcome to math with mr j [Music] in this video i'm going to cover the divisibility rule for eight now when we're talking divisibility that
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just means that we're checking to see if we can divide without getting a remainder so the given numbers work out exactly in the case of this video we have four numbers that we're going to go through and see
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if they are divisible by 8 based on the rule at the top of the screen so if the number formed by the last three digits is divisible by eight then the original number is divisible by
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eight so let's go through our examples and see what that rule means for number one we have 342 024
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so the last three digits are 0 2 and 4. so we get a 24 that's the number that is formed so if 24 is divisible by 8 that means the number
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three hundred forty two thousand twenty four is divisible by eight so can we do twenty four divided by eight and get an answer without a remainder yes twenty four divided by eight is three so twenty four is divisible by
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8 therefore our original number is divisible by 8.
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so we get a yes for number one on the number 2 where we have 184 778.
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so our last three digits here are 778 so we need to see if that number is divisible by 8. i'm not sure off the top of my head so let's go to the side
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here and do a quick division problem so we can't do out of the 7 so we need to go to the 77
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77 divided by 8 that is going to give us 9 whole 8 it gets us to 72
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subtract we get five bring down this eight so 58 how many whole groups of eight out of 58 well seven that gets us to 56 and we get a
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remainder of two so 97 remainder two 778 is not divisible by eight
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therefore our original number of 184 778 is not divisible by eight either so on to number three where we have nine million
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one hundred twenty five thousand forty eight so our last three digits gives us a 48 there and 48 is divisible by eight 48 divided by eight equals six without a
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remainder since those last three digits are divisible by eight nine million one hundred twenty-five thousand forty-eight is divisible by eight as well now lastly number four we have seven
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million ninety one thousand five hundred forty four so our last three digits here 544 i'm not sure off the top of my head so let's do a quick division problem
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off to the side here and we'll start with 54 divided by 8 so how many whole groups of 8 out of 54 well 6 that's going to get us
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to 48 we'll subtract and we get 6. bring down our 4 here and 64
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and 8 are compatible so 64 divided by 8 gives us an 8 8 times 8 64. and that shows that we do not have a
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remainder so 544 is divisible by 8 therefore our original number of seven million ninety-one thousand five hundred
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forty-four is divisible by eight as well so there you have it there's the divisibility rule for eight i hope that helped thanks so much for
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crypto rhythms crypto rhythms are puzzles which have an arithmetic expression where the digits are replaced by letters
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each digit a different letter some of them have a mix of alphabets and numbers and a few others have all alphabets and for the fun part
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some of these scripture rhythms have actual words and meaningful phrases before we start solving let's learn the
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rules that govern these crypto rhythms the first rule is that any number cannot start with a zero let's say we have this puzzle
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here send is a number more is another number and money will be another number the first digits of these numbers cannot
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take the value of zero so in our case s and m will never be a zero next rule in any given puzzle similar
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alphabets will have the exact same numerical value for example let's say we have this cryptalism here the s in sun
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and the s in swim should have the exact same numerical value third condition no two alphabets will have the same
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numerical value for example let's say in this crypto rhythm b has a value of two
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this means that none of the other alphabets can take a value of 2.
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finally after replacing all the alphabets with its numerical value the resulting expression must be mathematically correct now let us get started with our first
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cryptalism a b plus ba is dad the alphabets whose numerical value has to be found are a b
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and d first let us list out all the possible values these alphabets can take they are 0 to 9.
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according to our first rule the numbers a b b a and d a d cannot start with a zero this means that a b and d cannot be
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zero so let us first eliminate zero now listen carefully the sum of any two numbers can give a maximum carry
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of one only let's see how assume we add two double digit numbers the largest two digit number is 99
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so let's assume we add 99 and 99 what we get is 198
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which means the carry is 1.
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in our crypto rhythm also we add 2 double digit numbers and the carry is d which means d is equal to one
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now for better understanding we'll remove all the other digits also in our puzzle we'll replace d with one
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now according to our third rule no two alphabets can have the same numerical value so we can eliminate one from a
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and b so a and b can take any value from 2 to 9.
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